Question

the triangle has vertices D(-1,6), E(4,3), F(0,-4). draw an altitude from vertex D. Find an equation for the altitude from vertex D.

Answer 1

its a right angle triangle

Answer 2

so the side DE is the altitude

Answer 3

y = (3x-12 +15)/5

y = \(-\frac{3x+3}{5}\) if i did it right

Answer 4

and I dint.... bummer

Answer 5

y = -3/5 (x-4)+3 this part is right :)

Answer 6

the final answer given is y= -
4/7x+ 38/7

Answer 7

y = (-3/5)x +(12/5) +3

oh; then DE isnt the altitude

Answer 8

but its a right angle triangle and its given the altitude is DE

Answer 9

id have to draw it out to see it correctly;

Answer 10

k..i tried it though..and yes it is a right angle triangle

Answer 11

none of the slopes between lines are perpendicular; and none of the sides that I find fit the pytahg; i cant see it as a 90 degree triangle

Answer 12

slope are:

-10; 7/4; and -5/3

in order for this to be a right tri; 2 of these whould have to multiply to be -1

Answer 13

how do we get that

Answer 14

to find the altitude of d; we determine the slope of ef and take its reciprocal and negate it for our slope

7/4; becomes -4/7

now input out d point like this:

y = (-4/7)(x+1)+6 and solve

Answer 15

i get:

y = (-4/7)x - (38/7)

Answer 16

err... + 38/7 on the end; confused my signs

Answer 17

k..so we shld substitute the point (-1,6)??

Answer 18

yes


y = slope(x-Px)+Py

slope = -4/7 ; Px = -1; Py = 6

Answer 19

and y shld we take the reciprocal?

Answer 20

becasue perpendicular lines have that property to them; their slopes multiply to -1

if we have a slope of 7/4 we need to flip it to get 1

\[\frac{7}{4}*\frac{4}{7}=1\]
but we need it to be \(-1\) which is why we negate it after we flip it over

Answer 21

gotta head to class; have fun and good luck :)

Answer 22

thank u so much..:)