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Mathematics 11 Online
OpenStudy (anonymous):

help! if y=-2/3x+(-4), then one point on the graph would be (0,-4) and another would be (3,-6) right?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

hot. so i can use the prof's trick and plot (0,-4) then go down 2, and to the right three to plot another point.

OpenStudy (anonymous):

you mean you'd go UP 3 and to LEFT 2

OpenStudy (anonymous):

i mean down two from the (0,-4) and then right three

OpenStudy (anonymous):

both point u gave is wrong

OpenStudy (anonymous):

@nati.. you are right. ignore my previous post

OpenStudy (anonymous):

@rrakes both points are correct. x is in the numerator.

OpenStudy (anonymous):

put x=0 and as x is in numerator it becomes undefined thus for x=0 equation has no solution

OpenStudy (anonymous):

sorry denominator

OpenStudy (anonymous):

for x = 0, y =-4

OpenStudy (anonymous):

x is in the numerator

OpenStudy (anonymous):

its -2/3x now how could x be in nr

OpenStudy (anonymous):

he meant -2/3x as -0.66666x

OpenStudy (anonymous):

okk u r right then

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