Question

A circle shown in the diagram below has a center or (-5.3) and passes through point (-1,7)
What is the equation for this circle

Answer 1

use distance formula to find radius (distance between the 2 points)
r = sqrt(4^2 + 4^2)
r = sqrt(32)
r^2 = 32

general form:
(x-h)^2 + (y-k)^2 = r^2
center: (h,k)
(x+5)^2 + (y-3)^2 = 32

Answer 2

hey dumbcow when you are done can u help me please

Answer 3

Use the distance formula in finding the distance from the center to the line which will be considered as the RADIUS.
\[\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}\]
=\[\sqrt{(-1+5)^{2}+(7-3)^{?}}\]
=\[\sqrt{(-4)^{2}+(4^{2})}\]
\[r ^{2}=32\]

(x-h)+(y-k)=r^2
\[(x+5)^{2}+(y-3)^{2}=32\]

Answer 4

yeah where is your question?

Answer 5

my equation?
it is there with the squared.

Answer 6

can't you see it?
it is on the lower portion.