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Mathematics 23 Online
OpenStudy (anonymous):

You want a 50% strength solution of medicine. You have some 20% strength solution and 40 milliliters of a 90% strength solution. How much of the 20% strength solution do you have to add to the 90% solution to get a 50% strength solution? The answer is 53.3 ml. I need to know HOW to get THAT answerrrrrr !

OpenStudy (owlfred):

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OpenStudy (anonymous):

(40*.9+x*.2)/(40+x)=.5

OpenStudy (anonymous):

the numerator is the total ml of pure solution, denominator is total milliliters

OpenStudy (anonymous):

40 ml *.9 pure/ml + x ml *.2 pure/ml

OpenStudy (anonymous):

is that 40.9 or 40 times .9?

OpenStudy (anonymous):

40 times .9, x times .2

OpenStudy (anonymous):

does the equation make sense?

OpenStudy (anonymous):

yeah kind of

OpenStudy (anonymous):

no i dont get it ):

OpenStudy (anonymous):

ok if you have 40 millilters of 90% HCl solution how much pure HCl do you have?

OpenStudy (anonymous):

Idk ): 20% ?

OpenStudy (anonymous):

the strength is 90%, so there are .9 ml of HCl per 1 ml of solution. so 40*.9 is the amount of pure HCl. 40*.9=36

OpenStudy (anonymous):

HCI ?

OpenStudy (anonymous):

oh im just putting a random chemical in it doesnt matter

OpenStudy (anonymous):

oh ahaha okay

OpenStudy (anonymous):

haha sorry

OpenStudy (anonymous):

ok so there are 40*.9 ml from the 90% solution and there are x*.2 ml from the 20% solution where x is however many ml we add

OpenStudy (anonymous):

thats the numerator which is the total pure ml

OpenStudy (anonymous):

and the denominator is just the total ml of solution, 40+x

OpenStudy (anonymous):

pure ml/ total ml = concentration

OpenStudy (anonymous):

and the concentration we want is .5 so the whole thing is set equal to .5

OpenStudy (anonymous):

okay i get that part !

OpenStudy (anonymous):

Do we put anything for X ?

OpenStudy (anonymous):

we need to solve for x now, that is the amount we need to add to get .50 concentration solution

OpenStudy (anonymous):

so now its just an algebra problem

OpenStudy (anonymous):

ohhhhhhhh ok, i gettttttttt it (: Thanksssssssss

OpenStudy (anonymous):

you're welcome :)

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