Question

Equation of circle in standard form with the following center and radius:
Center (-8, -3), radius = 2

Answer 1

(x+8)^2+(y+3)^2=2^2

Answer 2

Ooops I mean radius 2 (3 squared)

Answer 3

Equation of circle in standard form is (x-h)^2 + (y-k)^2 =r^2 now your center is in
point (h,k)=(-8,-3),,just plug in your given point to the formula
(x-h)^2 + (y-k)^2 =r^2
(x-(-8))^2 + (y-(-3))^2 =2^2
(x+8)^2+(y+3)^2=2^2 or
(x+8)^2+(y+3)^2=4 ans...

Answer 4

did you get it wow? or is it clear now?..lol