use the root test to determine convergence or divergence
\[\sum_{n=4}^{\infty} (k/k+10)^{k}\]
what do u mean by k/k
k = numerator. k+10 = denominator fraction to the kth power
\[\lim_{k \rightarrow \infty }\sqrt[k]{(\frac{k}{k+10})^k}=\lim_{k \rightarrow \infty}\frac{k}{k+10}=1\]
but we can check that that t_k+1 >t_k so the series diverges
isn't infinity over infinity indeterminate?
yes it is . that is why we take a different approach to find this limit. Divide numerator and denominator by k. Hence, it is now limit as (1/k->0) 1/1+(1/k) = 1
if it is one then it's divergent by what test?
take \[\frac{t_{k+1}}{t _{k}}\]and u will find this is greater than 1
oh so its not = 1???
no root test gives u 1 but ratio test is >1
ohhh.. wow . and I want either < or > 1 right...
in root test u don't need t_{k+1}
yes...
wait but the problem stated to use the root test!
see u can solve it by ratio test...that easily gives u that the series is diverging..
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