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Mathematics 8 Online
OpenStudy (cherrilyn):

use the root test to determine convergence or divergence

OpenStudy (cherrilyn):

\[\sum_{n=4}^{\infty} (k/k+10)^{k}\]

OpenStudy (anonymous):

what do u mean by k/k

OpenStudy (cherrilyn):

k = numerator. k+10 = denominator fraction to the kth power

OpenStudy (anonymous):

\[\lim_{k \rightarrow \infty }\sqrt[k]{(\frac{k}{k+10})^k}=\lim_{k \rightarrow \infty}\frac{k}{k+10}=1\]

OpenStudy (anonymous):

but we can check that that t_k+1 >t_k so the series diverges

OpenStudy (cherrilyn):

isn't infinity over infinity indeterminate?

OpenStudy (anonymous):

yes it is . that is why we take a different approach to find this limit. Divide numerator and denominator by k. Hence, it is now limit as (1/k->0) 1/1+(1/k) = 1

OpenStudy (cherrilyn):

if it is one then it's divergent by what test?

OpenStudy (anonymous):

take \[\frac{t_{k+1}}{t _{k}}\]and u will find this is greater than 1

OpenStudy (cherrilyn):

oh so its not = 1???

OpenStudy (anonymous):

no root test gives u 1 but ratio test is >1

OpenStudy (cherrilyn):

ohhh.. wow . and I want either < or > 1 right...

OpenStudy (anonymous):

in root test u don't need t_{k+1}

OpenStudy (anonymous):

yes...

OpenStudy (cherrilyn):

wait but the problem stated to use the root test!

OpenStudy (anonymous):

see u can solve it by ratio test...that easily gives u that the series is diverging..

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