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OpenStudy (anonymous):
\[ g(x)=3\sqrt{}xe ^{x}\]
OpenStudy (anonymous):
Please show me step by step thanks
OpenStudy (anonymous):
3(sqrt(x)e^x)
OpenStudy (anonymous):
?
OpenStudy (anonymous):
3root(x)e^x + (3/2)(e^x)/root(x)
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OpenStudy (anonymous):
yea
OpenStudy (anonymous):
chain rule
first treat rootx as constant and diff e^x and then keep e^x constant and diff rootx
OpenStudy (anonymous):
3root(x)e^x + (3/2)(e^x)/root(x)
OpenStudy (anonymous):
Or just use product rule?
OpenStudy (anonymous):
i didnt learn the chain rule yet
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OpenStudy (anonymous):
can you show me please
OpenStudy (anonymous):
oh sorry product rule..i said chain rule by mistake
OpenStudy (anonymous):
Product Rule
OpenStudy (anonymous):
Horatio has a pack of candies containing 4 strawberry, 2 lemon, 1 lime, and 3 orange flavored chews, in random order. If he eats each candy immediately after taking it out of the pack, which multiplication expression can be used to determine the probability that the first two candies he eats are lemon?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
can you show me how to use the poduct rule for this problem
OpenStudy (anonymous):
see if there is a product of 2 functions
f(x)g(x)
the derivative is
f(x)g'(x) + f'(x)g(x)
OpenStudy (anonymous):
so now treat e^x as f(x) and rootx as g(x)
OpenStudy (anonymous):
ok..but where is 3
OpenStudy (anonymous):
3 u put outside..it is constant
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OpenStudy (anonymous):
o ok..so it would be like this\[3\sqrt{x}e^x = 3(1/2(x))^-1/2\]
OpenStudy (anonymous):
no sure it thats right
OpenStudy (anonymous):
wheres the e^x gne?
OpenStudy (anonymous):
o well that becomes \[e\]
OpenStudy (anonymous):
and its a constant so i removed it
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