suppose z=f(x,y) is a differentiable function on R^2 and x=rcos(theta) and y=rsin(theta). compute the partial of z with respect to r.
what is f(x,y)?
according to the question it can be anything.
damn. is this calc 2?
dx/dr = cos(theta) dy/dr = sin(theta)
calc 3
hmm say z = x+y then dz/dr = cos(theta) + sin(theta) i think, dang i have forgotten a lot of calc 3
lol. im in calc 1 :D cant rly help you
\[\frac{dz}{dr} = \frac{dz}{dx}\frac{dx}{dr} + \frac{dz}{dy}\frac{dy}{dr}\]
that's what I was thinking. that's the answer i have. do you have a link or something to that? i'll need that again for future reference.
no that i actually remembered i tried looking it up but no luck yet...
i know i've seen that somewhere myself. it was a vague memory but since you thought of the same thing i feel a lot better about it.
I agree with you guys it's called the total derivative. http://en.wikipedia.org/wiki/Total_derivative. The case you are interested in is a little bit down the page
thanks for the link. i feel much better now that two others agree.
thank you
can either of you help with lagrange multipliers?
for some reason my calc teachers never mentioned them.
what's the problem though I'll try to look it up and maybe I can help?
just posted it
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