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Mathematics 7 Online
OpenStudy (anonymous):

x^2+x<0 (Solve for x)

OpenStudy (mathteacher1729):

How far have you gotten on this problem? I am not sure where to begin helping without knowing what is giving you trouble.

OpenStudy (anonymous):

I dont understand how to solve for x when there are two x's, and one is squared?

OpenStudy (anonymous):

I would first start out by pulling an x out and make the inequality: x(x+1)<0

OpenStudy (anonymous):

so you factored it?

OpenStudy (anonymous):

yes factor it, that way you can solve it simply

OpenStudy (anonymous):

then what?

OpenStudy (anonymous):

then you know there will be 2 sides to the inequality. the x that is multiplying (x+1) will equal 0. then you need to solve x+1<0; this simplifies to x<-1. Therefore

OpenStudy (anonymous):

you get -1<x<0

OpenStudy (mathteacher1729):

http://www.wolframalpha.com type "x^2+x < 0" and you will get a graph with a nice explanation as well. Make sure you understand the graph. You are looking for the interval on which the function is less than zero.

OpenStudy (anonymous):

another way to do this is to draw the graph of y = x(x+1) - the area below the x-axis enclosed by the curve will give the solution

OpenStudy (anonymous):

ok thanks

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