x^2+x<0 (Solve for x)
How far have you gotten on this problem? I am not sure where to begin helping without knowing what is giving you trouble.
I dont understand how to solve for x when there are two x's, and one is squared?
I would first start out by pulling an x out and make the inequality: x(x+1)<0
so you factored it?
yes factor it, that way you can solve it simply
then what?
then you know there will be 2 sides to the inequality. the x that is multiplying (x+1) will equal 0. then you need to solve x+1<0; this simplifies to x<-1. Therefore
you get -1<x<0
http://www.wolframalpha.com type "x^2+x < 0" and you will get a graph with a nice explanation as well. Make sure you understand the graph. You are looking for the interval on which the function is less than zero.
another way to do this is to draw the graph of y = x(x+1) - the area below the x-axis enclosed by the curve will give the solution
ok thanks
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