The Utah Ski Club sells calendars to raise money. The profit P, in cents, from selling x calendars is given by the equation P(x)=360x-x2.
A.) find how many calendars must be sold to maximize profit.
B.) find the maximum profit.
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OpenStudy (amistre64):
utah?
OpenStudy (amistre64):
the vertex of will answer all your questions :)
OpenStudy (amistre64):
2x -360 = 0 x = 360/2 = 180
OpenStudy (anonymous):
maximum is at vertex which we now know is
\[\frac{-b}{2a}\]
OpenStudy (anonymous):
180 i think is the answer for the first one.
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OpenStudy (anonymous):
in this case it is 180
OpenStudy (anonymous):
then replace x by 180 and get your answer
OpenStudy (anonymous):
the profit is 180^2
OpenStudy (amistre64):
which after taxes is abot -.32
OpenStudy (anonymous):
actually profit is
\[P(180)=360\times 180-180^2\]
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OpenStudy (anonymous):
32400 which according to amistre rounds to -.32
OpenStudy (amistre64):
i got me a new book from library 2day
OpenStudy (anonymous):
don't forget the licensing fee
OpenStudy (anonymous):
and the bribe
OpenStudy (anonymous):
wadja get?
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OpenStudy (amistre64):
differential equations , second edition. its the sequal to differential equation, first edition lol