The Utah Ski Club sells calendars to raise money. The profit P, in cents, from selling x calendars is given by the equation P(x)=360x-x2. A.) find how many calendars must be sold to maximize profit. B.) find the maximum profit.
utah?
the vertex of will answer all your questions :)
2x -360 = 0 x = 360/2 = 180
maximum is at vertex which we now know is \[\frac{-b}{2a}\]
180 i think is the answer for the first one.
in this case it is 180
then replace x by 180 and get your answer
the profit is 180^2
which after taxes is abot -.32
actually profit is \[P(180)=360\times 180-180^2\]
32400 which according to amistre rounds to -.32
i got me a new book from library 2day
don't forget the licensing fee
and the bribe
wadja get?
differential equations , second edition. its the sequal to differential equation, first edition lol
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