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Mathematics 19 Online
OpenStudy (anonymous):

What value does ln(x)/(x-1) approach as x -> 1?

OpenStudy (amistre64):

1 if i see it right

OpenStudy (anonymous):

You get 0/0. Apply L'hospital's rule and take a derivative of top and bottom. That gives: (1/x)/1=1/x as that so: the lim x->1 (ln(x)/(x-1))=lim x->1 (1/x)=1

OpenStudy (anonymous):

you can use L'Hopitals rule since we have a 0/0 form

OpenStudy (anonymous):

yep it's 1

OpenStudy (anonymous):

whoops, my bad. l'hopital's rule is right.

OpenStudy (dumbcow):

yeah what everyone else said... :)

OpenStudy (amistre64):

general hospital said so ;)

OpenStudy (anonymous):

I can do it up in latex to make it look nicer if need be. :P

OpenStudy (amistre64):

i think im allergic to latex ....

OpenStudy (anonymous):

... you would xD

OpenStudy (anonymous):

that is your next book: differential equations 3 with latex

OpenStudy (amistre64):

mathmatical models of imaginary domains :)

OpenStudy (anonymous):

openstudy should send you one instead of the bike. maybe at 2000?

OpenStudy (anonymous):

functions of an almost complex variable

OpenStudy (amistre64):

openstudy aint sending me squat.... i got me name on a twitter..yay!!

OpenStudy (anonymous):

non reimannian hypercubes and a semi differentiable manifold

OpenStudy (amistre64):

now your just trying to turn me on :)

OpenStudy (anonymous):

HAHAHAHA GET IT ;)

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