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how would i write 16h to the -7th in positive exponents
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1/16h^7
-7? or -1/7 ?
\[1\div16h ^{7}\]
kind of like a fraction
\[\frac{16}{h^{+exp}}\]
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x^-1 can be written as 1/(x^1)
ty amistre
:D
i think amistre is wrong.. if i understand the question correctly
if the 16h looks like this: (16h) then you flip the whole thing :)
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yeah. it depends on what the -7 exponent is applied to
if its just: \[16h^{-exp}\] flip the h over
the =7 is an exponent
-7**
if it looks like (16h)^-7 then it would be 1/(16h)^7
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okay then
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