81^(3/4)...i know the answer is 27 but how do you get there? do u just divide 81 by 3?

Question

amistre64 · Answer

$$\sqrt[4]{81^3}$$ is the only way I can see it

smurfy14 · Answer

whts that mean?

amistre64 · Answer

81^(3/4) = y

3/4 ln(81) = y .... cant see it that way

it means you cube 81 and see what it 4roots into

smurfy14 · Answer

ok well how do you solve??

amistre64 · Answer

there is prolly an elegant algorithm for it; but i just have to brute math it:

4rt(81^3)

4rt(531441) = n

531441 = n^4

amistre64 · Answer

then i trial and error it till I reach 27

anonymous · Answer

81^3/4 = 3^(4*3/4) = 3^3 = 27

anonymous · Answer

notice that 81 = 9*9 and 9 = 3*3
so 81 = 3*3*3*3 = 3^4

smurfy14 · Answer

how did you get the (4*3/4) part?

amistre64 · Answer

Y=f'(x)(x-xo)+f(xo) perhaps?

anonymous · Answer

$$81^{3/4} = (3^{4})^{3/4} = 3^{4*3/4} = 3^{3} =27$$

smurfy14 · Answer

amistre your making it too complicating for me lol

amistre64 · Answer

:)  srry

smurfy14 · Answer

oohhh ok thank you soooo much dhatraditya :D

anonymous · Answer

you are welcome. :)

mathteacher1729 · Answer

$$81= 3*3*3*3 $$

So we're looking for $$ ((81)^{1/4})^3$$
Notice that
$$ ((3)^4)^{1/4} = 3$$
and
$$3^3 = 27$$