Find the vertices of the hyperbola with equation: ((x+2)^2/4)-((y+1)^2/16)=1

Question

owlfred · Answer

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amistre64 · Answer

16 is not it casue its under the negatve

amistre64 · Answer

sqrt(4) = 2; so the are 2 from center parallel to the x axis

amistre64 · Answer

center = (-2,-1)

so verts are (-4,-1)  and (0,-1)

anonymous · Answer

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anonymous · Answer

Okay(: There you go. Thank you!

amistre64 · Answer

:)  youre welcome

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