Solve x^(4/3)=81
81^(3/4)
why did you do that?
\[x^\frac{4*3}{3*4}=81^\frac{3}{4}\]
oh mine that isn't readable
whyd you multiply 4*3? its a fraction?
x^(4/3) = cube root (x^4) If you cube both sides, you get: x^4 = 81^3 x^4 = 531,441 Take the 4th root of both sides and you get: x = 27
if we multiply the exponent on the left side by 3/4, then we have to multiply the exponent on the right side by 3/4. the reason we chose 3/4 is because 4/3*3/4=1 so this we give us x^1 or x
81^(3/4)=27
x^(2/3)=8 then x=8^(3/2)
if we have x^(4/5)=1231 then x=1231^(5/4)
ok so is that just like a rule that u always do? andd it would be the same thing as 4/3logx=log81 right?
if we have x^(3/2)=8, then x=8^(2/3) and x=(-8)^(2/3) because it is okay to have an odd root with a negative inside
so are you saying the answer is 27 AND -27?
logx^(4/3)=log81 x^(4/3)=81 yes same thing x=81^(3/4)
no we had an even root for that one see the root at the end it is 4 (which is even)
x^(2/3)=4 =>x=4^(3/2) (we raised both sides with even root so one answer) x^(3/2)=4 =>x=4^(2/3) and x=(-4)^(2/3) (we raised both sides with odd root)
i have to do something i might be back in a few seconds or minutes
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