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Mathematics 14 Online
OpenStudy (anonymous):

tan(-3pie/2)

OpenStudy (anonymous):

infinity

OpenStudy (anonymous):

and its pi not pie

OpenStudy (anonymous):

oh my bad.thanks.

OpenStudy (anonymous):

although at mit they celbrate pi day by having pie...

OpenStudy (anonymous):

thats funny

OpenStudy (anonymous):

wait...how did you get infinity?. we are suppose to use the unit circle.

OpenStudy (anonymous):

the x coordinate of a point on the unit circle is cosine isnt it? and the y-coordinate is sine\?? so when you divide them u get tan..for -3pi/2 y=1, x=0

OpenStudy (anonymous):

as u can use the same values for -3pi/2 and pi/2

OpenStudy (anonymous):

get it??

OpenStudy (anonymous):

so tan would not be 1/0 and make it undefined?

OpenStudy (anonymous):

yeah...infinity

OpenStudy (anonymous):

or you can say tending to infinity

OpenStudy (anonymous):

oh..ok thanks!

OpenStudy (anonymous):

are you busy because I had 3 other similar ones?

OpenStudy (anonymous):

fire away bt i wont answer straightaway..u need to learn

OpenStudy (anonymous):

ok good..csc5pi

OpenStudy (anonymous):

try....wts cosec defined AS?

OpenStudy (anonymous):

its 1/y

OpenStudy (anonymous):

wts y?

OpenStudy (anonymous):

0?

OpenStudy (anonymous):

how?

OpenStudy (anonymous):

because 5pi-2pi=3pi then 3pi-2pi=pi so the y value of pi is 0

OpenStudy (anonymous):

yeah ur right..so wts ur final answer?

OpenStudy (anonymous):

so 1/0 which means its undefined or infinity

OpenStudy (anonymous):

right

OpenStudy (anonymous):

ok. next one is sec(-pi/4)

OpenStudy (anonymous):

go the same way...sec is dfined as?

OpenStudy (anonymous):

1/x and x is \[\sqrt{2}/2\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so 1/sqrt{2}/2 then i rationalize and get sqrt2/2?

OpenStudy (anonymous):

u just cancel one sqrt 2 and get 1/sqrt(2)

OpenStudy (anonymous):

so then sec is 1/x, so sec is sqrt(2)

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

and does it matter if it is - pi?

OpenStudy (anonymous):

not in this case bcoz cos(-pi) = cos(pi)

OpenStudy (anonymous):

or infact cos(x) = cos(-x)

OpenStudy (anonymous):

so it does not make a difference

OpenStudy (anonymous):

not here...

OpenStudy (anonymous):

ok is cot(-4pi/3) equal to 1/sqrt3

OpenStudy (anonymous):

-1/sqrt(3)

OpenStudy (anonymous):

ok so in this case it would be - i see.

OpenStudy (anonymous):

look at the unit circle...-4pi/3 lies in the second quadrant...here cos is -ve and sin is +ve so the ratio is negative..look at it this way

OpenStudy (anonymous):

just imagine the unit circle in ur head and ull solve everythng

OpenStudy (anonymous):

isnt it in the third quadrant?..and ok i will just memorize

OpenStudy (anonymous):

second....just swing ur radius 240 degrees clockwise from the +ve x-axis

OpenStudy (anonymous):

oh ok because its -

OpenStudy (anonymous):

thanks so much for your help!

OpenStudy (anonymous):

welcome

OpenStudy (anonymous):

just to add my 2 cents on a saturday, \[\frac{1}{0}\] is undefined. it is not not i repeat not infinity

OpenStudy (anonymous):

from your very example here you have \[\tan(-\frac{3\pi}{2})\] which, if you just plug in the numbers would give \[\frac{-1}{0}\] and this certainly does't tend to infinity as x approaches \[\frac{-3\pi}{2}\] because from on direction tangent would increase with out bound to \[\infty\] but from the other direction it would go to \[-\infty\]

OpenStudy (anonymous):

just thought i would mention it

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