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OpenStudy (anonymous):
infinity
OpenStudy (anonymous):
and its pi not pie
OpenStudy (anonymous):
oh my bad.thanks.
OpenStudy (anonymous):
although at mit they celbrate pi day by having pie...
OpenStudy (anonymous):
thats funny
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OpenStudy (anonymous):
wait...how did you get infinity?. we are suppose to use the unit circle.
OpenStudy (anonymous):
the x coordinate of a point on the unit circle is cosine isnt it? and the y-coordinate is sine\?? so when you divide them u get tan..for -3pi/2 y=1, x=0
OpenStudy (anonymous):
as u can use the same values for -3pi/2 and pi/2
OpenStudy (anonymous):
get it??
OpenStudy (anonymous):
so tan would not be 1/0 and make it undefined?
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OpenStudy (anonymous):
yeah...infinity
OpenStudy (anonymous):
or you can say tending to infinity
OpenStudy (anonymous):
oh..ok thanks!
OpenStudy (anonymous):
are you busy because I had 3 other similar ones?
OpenStudy (anonymous):
fire away bt i wont answer straightaway..u need to learn
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OpenStudy (anonymous):
ok good..csc5pi
OpenStudy (anonymous):
try....wts cosec defined AS?
OpenStudy (anonymous):
its 1/y
OpenStudy (anonymous):
wts y?
OpenStudy (anonymous):
0?
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OpenStudy (anonymous):
how?
OpenStudy (anonymous):
because 5pi-2pi=3pi then 3pi-2pi=pi so the y value of pi is 0
OpenStudy (anonymous):
yeah ur right..so wts ur final answer?
OpenStudy (anonymous):
so 1/0 which means its undefined or infinity
OpenStudy (anonymous):
right
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OpenStudy (anonymous):
ok. next one is sec(-pi/4)
OpenStudy (anonymous):
go the same way...sec is dfined as?
OpenStudy (anonymous):
1/x and x is \[\sqrt{2}/2\]
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
so 1/sqrt{2}/2 then i rationalize and get sqrt2/2?
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OpenStudy (anonymous):
u just cancel one sqrt 2 and get 1/sqrt(2)
OpenStudy (anonymous):
so then sec is 1/x, so sec is sqrt(2)
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
and does it matter if it is - pi?
OpenStudy (anonymous):
not in this case bcoz cos(-pi) = cos(pi)
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OpenStudy (anonymous):
or infact cos(x) = cos(-x)
OpenStudy (anonymous):
so it does not make a difference
OpenStudy (anonymous):
not here...
OpenStudy (anonymous):
ok is cot(-4pi/3) equal to 1/sqrt3
OpenStudy (anonymous):
-1/sqrt(3)
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OpenStudy (anonymous):
ok so in this case it would be - i see.
OpenStudy (anonymous):
look at the unit circle...-4pi/3 lies in the second quadrant...here cos is -ve and sin is +ve so the ratio is negative..look at it this way
OpenStudy (anonymous):
just imagine the unit circle in ur head and ull solve everythng
OpenStudy (anonymous):
isnt it in the third quadrant?..and ok i will just memorize
OpenStudy (anonymous):
second....just swing ur radius 240 degrees clockwise from the +ve x-axis
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OpenStudy (anonymous):
oh ok because its -
OpenStudy (anonymous):
thanks so much for your help!
OpenStudy (anonymous):
welcome
OpenStudy (anonymous):
just to add my 2 cents on a saturday, \[\frac{1}{0}\] is undefined. it is not not i repeat not infinity
OpenStudy (anonymous):
from your very example here you have
\[\tan(-\frac{3\pi}{2})\] which, if you just plug in the numbers would give
\[\frac{-1}{0}\] and this certainly does't tend to infinity as x approaches
\[\frac{-3\pi}{2}\] because from on direction tangent would increase with out bound to \[\infty\] but from the other direction it would go to
\[-\infty\]
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