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z^-1+(12z)^-1
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\[13z^-2\]
its 13 z power -2 ok
thats not right
Okay the answer is \[13/12z\]
z^-1+(12z)^-1 1/z+1/12z=(12+1)/12z=13/12z
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The reason for this is that since we are dealing with negative exponents, thus we try and make them positive. Do accomplish this we take the reciprocal of each negative exponent. In this case: \[z^-1 becomes 1 /z^1 or just 1/z\] Also,\[ 12z^-1 becomes 1/12z^1 or just 1/12z\] Then we simply find the lcd in this case 12z, thus: we multipy the first fraction (top and bottom) by 12: \[12(1/z)= 12/12z\] Now the problem is: \[12/12z + 1+12z\] This simply becomes: 13/12z
13/(12z)
\[z ^{2} -1 + \dfrac{1}{12z} \] multiply the whole expression by \[\dfrac{12z}{12z}\], then you get \[12z^3-12z+1\]
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