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Mathematics 22 Online
OpenStudy (anonymous):

z^-1+(12z)^-1

OpenStudy (anonymous):

\[13z^-2\]

OpenStudy (anonymous):

its 13 z power -2 ok

OpenStudy (anonymous):

thats not right

OpenStudy (anonymous):

Okay the answer is \[13/12z\]

OpenStudy (angela210793):

z^-1+(12z)^-1 1/z+1/12z=(12+1)/12z=13/12z

OpenStudy (anonymous):

The reason for this is that since we are dealing with negative exponents, thus we try and make them positive. Do accomplish this we take the reciprocal of each negative exponent. In this case: \[z^-1 becomes 1 /z^1 or just 1/z\] Also,\[ 12z^-1 becomes 1/12z^1 or just 1/12z\] Then we simply find the lcd in this case 12z, thus: we multipy the first fraction (top and bottom) by 12: \[12(1/z)= 12/12z\] Now the problem is: \[12/12z + 1+12z\] This simply becomes: 13/12z

OpenStudy (anonymous):

13/(12z)

OpenStudy (anonymous):

\[z ^{2} -1 + \dfrac{1}{12z} \] multiply the whole expression by \[\dfrac{12z}{12z}\], then you get \[12z^3-12z+1\]

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