2x^2-17=5x write each equaton in standord form and determine (A)

Question

2x^2-17=5x write each equaton in standord form and determine (A)< (B)< and (C)

anonymous · Answer

sorry (A) (B) (C)

anonymous · Answer

there is no $$a\ , b\ , c$$

anonymous · Answer

my prob. says write each equation in standord form and determine (A), (B), and (C)
2x^2-17=5x

anonymous · Answer

quadratic equation standard form is $$ax^2+bx+c=0$$. So, what do you do to transform the expression $$2x^2-17=5x$$ into $$ax^2+bx+c=0$$ Check out: http://www.oojih.com/show/algebra/quadraticfunction/

anonymous · Answer

$$The \ standard\ form\ is\ 2x^2 - 5x +17 = 0$$

anonymous · Answer

Krish, not quite right

anonymous · Answer

standard form is 2x^2 - 5x -17 = 0

a=2, b= -5 and c = -17

anonymous · Answer

@chloebella

Basically u hv to shift all terms to one side as i do, keeping in mind the change of sign when u shift the term

after that the coefficient of x^2 term is a
coefficient of x term is b
and constant term is c

anonymous · Answer

Got it?????

If yes, pls click GOOD ANSWER to close the question

anonymous · Answer

already gave u a medal