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Mathematics 11 Online
OpenStudy (anonymous):

x^2+1 divided by 3x^5-x^3+6x^2-11x+6

OpenStudy (amistre64):

good luck with it....

OpenStudy (amistre64):

maybe if you post it a few more times it will magically get solved :)

OpenStudy (anonymous):

there is a remainder in the answer im assuming

OpenStudy (anonymous):

when you divide it out and this is a different problem

OpenStudy (amistre64):

different really? gonna have to read it then ;)

OpenStudy (amistre64):

youre right lol; after awhile they all look the same, srry :)

OpenStudy (amistre64):

still cant get a divide on it.....

OpenStudy (anonymous):

yes you can your just gonna have a remainder

OpenStudy (anonymous):

There is a remainder in the answer amistre gave you. What is the answer to the question since you said it is wrong.

OpenStudy (amistre64):

the remainder I gave last time I tried was to see if they factored to simplify

OpenStudy (amistre64):

4 --- can divide out since we have decimals to convert to 111

OpenStudy (amistre64):

but this?

OpenStudy (amistre64):

is there an example problem they give you?

OpenStudy (anonymous):

u divide it out and get your remainder and put it over the x^2+1

OpenStudy (anonymous):

yes but i am having trouble dividing it out to get the remainder

OpenStudy (amistre64):

\[\frac{x^2+1}{3x^5-x^3+6x^2-11x+6}\] is what you have written

OpenStudy (amistre64):

do you mean to say that that is backwards then?

OpenStudy (amistre64):

\[\frac{3x^5-x^3+6x^2-11x+6}{x^2+1}\] might be what you wanna find?

OpenStudy (anonymous):

yes

OpenStudy (amistre64):

OpenStudy (amistre64):

3x^5-x^3+6x^2-11x+6 divided by x^2+1 is the question then .....

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