x^2+1 divided by 3x^5-x^3+6x^2-11x+6
good luck with it....
maybe if you post it a few more times it will magically get solved :)
there is a remainder in the answer im assuming
when you divide it out and this is a different problem
different really? gonna have to read it then ;)
youre right lol; after awhile they all look the same, srry :)
still cant get a divide on it.....
yes you can your just gonna have a remainder
There is a remainder in the answer amistre gave you. What is the answer to the question since you said it is wrong.
the remainder I gave last time I tried was to see if they factored to simplify
4 --- can divide out since we have decimals to convert to 111
but this?
is there an example problem they give you?
u divide it out and get your remainder and put it over the x^2+1
yes but i am having trouble dividing it out to get the remainder
\[\frac{x^2+1}{3x^5-x^3+6x^2-11x+6}\] is what you have written
do you mean to say that that is backwards then?
\[\frac{3x^5-x^3+6x^2-11x+6}{x^2+1}\] might be what you wanna find?
yes
3x^5-x^3+6x^2-11x+6 divided by x^2+1 is the question then .....
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