Question

Help! Can somebody help me figure out how to use this online graphing calculator? Here's the link..http://my.hrw.com/math06_07/nsmedia/tools/Graph_Calculator/graphCalc.html

Answer 1

are you actually trying to graph something?

Answer 2

If so, all you have to do is put the function into y1. To graph multiple functions, put them into y1 y2 and y3.

Answer 3

then select "Graph"

Answer 4

is function the same thing as equation?

Answer 5

Yes if its in y= form

Answer 6

What if you're trying to graph a system like the below:
2x + y = 6
3x - 2y = 2

Answer 7

then you must solve for y.
y=-2x+6
y= -(3/2)x - 1

Answer 8

do you understand how I did that?

Answer 9

Yes...so I just type a y=? form in the y columns, then press graph, right?

Answer 10

right.

Answer 11

I pressed 'graph', and it just gave me a blank coordinate system...

Answer 12

did you try those two that you gave me?

Answer 13

Yes, after I put them in your simplified y=? form...I've zoomed in and out and I still don't see anything...

Answer 14

hmm... did you enter "y=-2x+6" or "-2x+6" ?

Answer 15

-2x+6

Answer 16

oops! actually i put this in..y=-2x+6

Answer 17

so how do I put all this in? Do I not put in the y?

Answer 18

you don't put the Y because it is already set up as Y1=, Y2=

Answer 19

Another thing that I noticed, is you usually dont need parenthesis. I tried -(3/2)x-1 and nothing showed up, but it works with -3/2x+1.
did you get it working?

Answer 20

Yes, I got one line graphed, with the parenthesis also..

Answer 21

So, how do I get the solution? I can't tell it for sure, just by looking at the graph..

Answer 22

what do you need to find?

Answer 23

The value of x and y, in both equations for this system..

Answer 24

well the value of x and y by themselves is the equation. usually you are asked to find the intercepts, or what x is when y=4 for example.

Answer 25

This is the whole problem..Ungraded
systems 23:

Solve the following system (if possible) and present your answer below:
2x + y = 6
3x - 2y = 2

Answer 26

it says ungraded, because it's from a practice test..

Answer 27

and for some reason, it's set up just like the actual quizzes and tests online, that are graded...

Answer 28

okay to solve the system you have to find where the two graphs meet

Answer 29

This is the solution that the practice test said, after I did it wrong...x = 2, y = 2
I only have one line on the graph here...I don't have two lines intersecting.

Answer 30

didnt you graph two equations for the problem?

Answer 31

I thought I did..do I have to press the graph button twice or something?

Answer 32

thats what i was saying about the parenthesis, take them out

Answer 33

Ok, I now have two lines intersecting..once I took the parenthesis out..

Answer 34

Oh and I made a mistake, the second is y=3/2x-1 not -3/2

Answer 35

ok..

Answer 36

now the graphs intersect at 2, 2

Answer 37

I see it now...thanks for helping out on using this...I tried to do my past quiz on this subject totally on graph paper and using a normal calculator...

Answer 38

I had done pretty good doing it this way on my exercise problems and practice test, with no time limit...

Answer 39

But I guess I can't do it this way being rushed, with a time limit...I'll be using this calculator from now on...thanks. :)

Answer 40

I think there is a faster way to do this, without a calculator.

Answer 41

by setting the equations of the system equal to each other then solving this equation

Answer 42

Steps for the algebraic method:
make sure that each linear equation is reduced to slope intercept form
(ie y=3x+2 is good but 2y=6x+4 is NOT)
set the two equations equal to each other
2x+1=4x-1
Solve for X
2x+1=4x-1
2=2x
x= 1
insert x value into either equation to determine y coordinate of solution
4(1)-1=3
The solution is the ordered pair you've just calculated
(1,3)

Answer 43

are you still here?