Find the relative extrema, the domain and range, the x and y intercepts, the asymptotes, and the slope of f'(x) at x=12. f(x)=(2x^2-36)/(x^2-144)
This would be a perfect problem to work through in geogebra. :)
Take a derivative to find the extrema (set f'(x)=0) To find the slope at 12 plug it in to the derivative f'(12)=?. The x intercepts, set y=0, y intercepts set x=0. The asymptotes are where the denominator is zero or (x^2-144)=(x+12)(x-12). Take a limit as x->infty and -infty to find any horizontal/slant asymptotes. The domain is all real numbers that don't make it undefined (12 and -12 in this case) Since there is a horizontal asymptote, the range may be a bit tricky :P
its tedious
It is, but graphing it is nice. Because derivatives allow you to get quick sketches (most of the time). At least in 2-space they do.
you wouldnt get the total credit in an exam but you know what you have to do good
well, we gotta throw out the cartesian plane then
Total credit? x.x
use a new geometry of units to measure the relationship between more than 3 variables
Here is the visual explanation of your problem. :) You should be able to graph most of this by hand using the methods malevolence described.
Join our real-time social learning platform and learn together with your friends!