Question

solve sec^2(x) over the interval [-pi/2, 5pi/2]

I am stumped with this one at the moment - thanks for any help!

Answer 1

Hoot! You just asked your first question! Hang tight while I find people to answer it for you. You can thank people who give you good answers by clicking the 'Good Answer' button on the right!

Answer 2

solve sec^2(x)..wts that mean?

Answer 3

hi

Answer 4

do you want us to integrate?

Answer 5

or solve sec^2(x)= (blank)

Answer 6

not sure: here is one of the multiple choices that I chose (as wrong) {0,5/2pi}

Answer 7

oh my bad; sec^2(x)=1

Answer 8

ok that makes more sense.

Answer 9

haha! sorry

Answer 10

I am really rusty with my unit circle trig if you can explain how you do it too that would be a huge help!

Answer 11

sec^2(x)=1/(cos^2(x))=1
cos^2(x)=1
cos(x)=+/- 1
x=Pi *n where n is an integer. so find the multiples of Pi that are in that interval

Answer 12

{0, Pi, 2Pi}

Answer 13

I got to the part just before cos(x)=+/- 1; how can you change cos^2(x)=1 like you did? thanks

Answer 14

square root of both sides

Answer 15

haha - thanks!

Answer 16

yep :)

Answer 17

so you simply reduced it to the point that you could plot it on the unit circle?

Answer 18

it basicaly means cos(x)=+1 or -! solution. so cosx takes those values for 0 ,pi ,2pi

Answer 19

i reduced it to a trig equation I know the result of. cos(x) takes on 1 and -1 at any multiple of Pi

Answer 20

cosx=1/secx and so it is posible to write cosx=+/-1 from sec^2(x)=+/-1

Answer 21

Thank, that all makes sense: how did you interpret the range part of the question though?

Answer 22

i found all the integer multiples of Pi that fall within the given interval

Answer 23

3Pi was too large, -1 Pi too small, 0, Pi, 2Pi work

Answer 24

gotcHA

Answer 25

out of interest how would 3 pi plot on the unit circle - if there was no range given in the question?

Answer 26

would the answer change if the question were sin(x)+/- Pi?

Answer 27

Thank you all for your help!