Question

how do u solve sqrt(x+4)=sqrt(x)+1

Answer 1

and show me the steps

Answer 2

\[\sqrt{x+4}=\sqrt{x}+1\]
square both sides
\[(\sqrt{x+4})^2=(\sqrt{x}+1)^2\]
\[x+4=\sqrt{x}\sqrt{x}+2\sqrt{x}+1\]
\[x+4=x+2\sqrt{x}+1\]
subtract x on both sides
also subtract 1 on both sides
\[x-x+4-1=2\sqrt{x}\]
\[3=2\sqrt{x}\]
divide both sides by 2
\[\frac{3}{2}=\sqrt{x}\]
now square both sides
\[(\frac{3}{2})^2=(\sqrt{x})^2\]
\[\frac{9}{4}=x\]

Answer 3

very nice

Answer 4

like this one?

Answer 5

aww your so sweet :)
its the same as the last one

Answer 6

really?

Answer 7

this is a car

Answer 8

its still the red one lol

Answer 9

the last one was a bike

Answer 10

can u stop typing please

Answer 11

i didn't see a bike

Answer 12

can help me with one more

Answer 13

solve the equation 3^(x+6)=4

Answer 14

\[3^{x+6}=4\]
\[(x+6)\ln(3)=\ln(4)\]
\[xln(3)+6\ln(3)=\ln(4)\]
\[x\ln(3)=\ln(4)-\ln(6)\]
\[x=\frac{\ln(4)-\ln(6)}{\ln(3)}\]

Answer 15

i made a mistake

Answer 16

lol you did 6ln3 does not equal ln6

Answer 17

should be
\[x\ln(3)=\ln(4)-6\ln(3)\]

Answer 18

so
\[x=\frac{\ln(4)-6\ln(3)}{\ln(3)}\]

Answer 19

satellite im gonna give you medals for everything
we are gonna get you built up
i'm gonna go om amistre medal strike

Answer 20

you can combine the logs in the numerator if you like but i wouldn't bother

Answer 21

i will never catch up but thanks anyway.

Answer 22

you can write it has two separate fractions and cancel the ln3 from the last fraction

Answer 23

now it is beer o'clock. later

Answer 24

\[x=\frac{\ln4}{\ln3}-6\]