what makes this equation true
here r the questions
help me please
Hey marxin :P
Okay for the first one:Add the 4 sqrt(2a)=6 square both sides: 2a=36 divide by 2. a=18
For the second one, I would factor out the - giving: x^2+4x+3=0 This gives you (x+1)(x+3) so your solutions are -1 and -3
hold on do 10 some on another page did 6-9
The next one might be a bit tricky to explain. But I'll do my best. You need to get a common denominator on the left. \[\frac{20(n-2)-1(n+2)}{(n-2)(n+2)}=\frac{15}{(n-2)(n+2)}\]. So the top must equal 15.
Okay. 10 then: You just need to use the quadratic formula. \[\frac{8 \pm \sqrt{(-8)^2-4(-1)(1)}}{2(1)}\].
hello???
I'm here, you want 11 too? :P You said 10 haha
oh srry yea 11 would be awesom alsowhere u at in da world
Virginia, US let me look at it, 2 seconds
Atlanta, Georgia here
Okay, start my multiplying by 9 and x: \[9(8+x)=x(x+10)\]. Gives: \[72+9x=x^2+10x\]. Combining: x^2+x-72=0 Which factors to: (x+9)(x-8)=0
So the answer is x= +8 and -9. You just have your signs switched again :P
thnaks man
No problem :P
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