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Mathematics 8 Online
OpenStudy (anonymous):

what makes this equation true

OpenStudy (anonymous):

here r the questions

OpenStudy (anonymous):

help me please

OpenStudy (anonymous):

Hey marxin :P

OpenStudy (anonymous):

Okay for the first one:Add the 4 sqrt(2a)=6 square both sides: 2a=36 divide by 2. a=18

OpenStudy (anonymous):

For the second one, I would factor out the - giving: x^2+4x+3=0 This gives you (x+1)(x+3) so your solutions are -1 and -3

OpenStudy (anonymous):

hold on do 10 some on another page did 6-9

OpenStudy (anonymous):

The next one might be a bit tricky to explain. But I'll do my best. You need to get a common denominator on the left. \[\frac{20(n-2)-1(n+2)}{(n-2)(n+2)}=\frac{15}{(n-2)(n+2)}\]. So the top must equal 15.

OpenStudy (anonymous):

Okay. 10 then: You just need to use the quadratic formula. \[\frac{8 \pm \sqrt{(-8)^2-4(-1)(1)}}{2(1)}\].

OpenStudy (anonymous):

hello???

OpenStudy (anonymous):

I'm here, you want 11 too? :P You said 10 haha

OpenStudy (anonymous):

oh srry yea 11 would be awesom alsowhere u at in da world

OpenStudy (anonymous):

Virginia, US let me look at it, 2 seconds

OpenStudy (anonymous):

Atlanta, Georgia here

OpenStudy (anonymous):

Okay, start my multiplying by 9 and x: \[9(8+x)=x(x+10)\]. Gives: \[72+9x=x^2+10x\]. Combining: x^2+x-72=0 Which factors to: (x+9)(x-8)=0

OpenStudy (anonymous):

So the answer is x= +8 and -9. You just have your signs switched again :P

OpenStudy (anonymous):

thnaks man

OpenStudy (anonymous):

No problem :P

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