Question

how do u solve 2/x+3-6/x-3=12/x^2-9

Answer 1

\[\frac{2}{x+3}-\frac{6}{x-3}=\frac{12}{x^2-9}\]

Answer 2

multiply both sides by
\[x^2-9\]

Answer 3

on the right you will get 12. on the left you will get
\[2(x-3)-6(x+3)\] because
\[x^2-9=(x+3)(x-3)\]

Answer 4

so the factors will cancel. now solve
\[2(x-3)-6(x+3)=12\]
\[2x-6-6x-18=12\]
\[-4x-24=12\]
\[-4x=12+24=36\]
\[x=\frac{36}{-4}=-9\]

Answer 5

let me check it to makes sure i didn't make a mistake

Answer 6

looks right

Answer 7

so the anwer is -9

Answer 8

yeah

Answer 9

yah i got that

Answer 10

that is what i got but i still want to check with the original equation to see that i did not make a careless algebra mistake

Answer 11

can u help me with this one

Answer 12

nm

Answer 13

sure

Answer 14

btw it is right i checked. get \[\frac{1}{6}\] on both left and right

Answer 15

so the aswere is -9 right

Answer 16

so its the anwer -9