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OpenStudy (anonymous):
Please help and explain this problem. Preferably step by step. Thanks!! A 3000kg train accelerates from rest to a velocity of 30m/s in 10s. The engine's power during this acceleration is ______.
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OpenStudy (anonymous):
I think it is 27kw
OpenStudy (anonymous):
energy =power x time
OpenStudy (anonymous):
power = energy/time
OpenStudy (anonymous):
now the energy you are dealing with in this case is kinetic energy, which is (1/2)mv^2
OpenStudy (anonymous):
so\[P=\frac{ \frac{1}{2} (3000) ( 30^2) }{10} Watts\]
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OpenStudy (anonymous):
then use a claculator to evaluate that
OpenStudy (anonymous):
Power=135000W=135kW
OpenStudy (anonymous):
Please post these in the PHYSICS section...
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