OpenStudy (anonymous):

Please help and explain this problem. Preferably step by step. Thanks!! A 3000kg train accelerates from rest to a velocity of 30m/s in 10s. The engine's power during this acceleration is ______.

6 years ago
OpenStudy (anonymous):

I think it is 27kw

6 years ago
OpenStudy (anonymous):

energy =power x time

6 years ago
OpenStudy (anonymous):

power = energy/time

6 years ago
OpenStudy (anonymous):

now the energy you are dealing with in this case is kinetic energy, which is (1/2)mv^2

6 years ago
OpenStudy (anonymous):

so\[P=\frac{ \frac{1}{2} (3000) ( 30^2) }{10} Watts\]

6 years ago
OpenStudy (anonymous):

then use a claculator to evaluate that

6 years ago
OpenStudy (anonymous):

Power=135000W=135kW

6 years ago
OpenStudy (anonymous):

Please post these in the PHYSICS section...

6 years ago