Simplify the expression: \[\sqrt[5]{96}+\sqrt[5]{3}\]
i get an answer but i can't get it to come out right...
for solving this , 96=2^5*3 and hence simplifying u get answer as, \[3\times3 ^{1/5}\]
why 3 times 3^1/5? why not 3 + 3^1/5 as in the original?
simplifying the first expression we hav, \[(2*2*2*2*2*3)^{1/5} + 3^{1/5}\] now from the first bracket,u take ou 2 and hence u get \[2\times3^{1/5}+3^{1/5}= 3^{1/5}(2+1)=3\times3^{1/5}\]
and the 1 comes from where? in the (2+1)?
oh i think i see it. the 3^1/5 is factored... right?
yea its is \[2\times3^{1/5}+1\times3^{1/5}\]
krish, i thought you were leaving. lol
\[hey\ basket \ math\ , \ do \ u\ know\ latex\ ?\]
not sure that i do. is that a joke? or a person?
\[I want\ some\ help\]
with what?
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