Question

hey can pls anyone solve this question
integration sign x/x^2+1 dx

Answer 1

now, \[x \div(x ^{2}+1)=2x \div2(x ^{2}+1)\]

Answer 2

ln(t+1)/2+c , wer t=x^2 :)

Answer 3

got it ?

Answer 4

let \[x ^{2}+1 = z\]
or, \[2xdx = dz\]

now, \[\int\limits_{}^{} [x \div (x ^{2} + 1)] dx\]
= \[\int\limits_{}^{} dz/z\]
= \[\ln z + c\]
= \[\ln (x ^{2}+1) + c\]

Answer 5

@ toriqur : well done , but u missed a 2 while substituting :) xdx=dz/2 !

Answer 6

oh, sorry. really i am. just a mistake, bro.

Answer 7

;)

Answer 8

i still didnt get it :(