Question

lx-4l=lx-7l (Solve for x)

Answer 1

step by step pls

Answer 2

for solving equations like these, use graphs. |x-4| is a v-graph @ x=4, similarly |x-7| is a v-graph @ x=7, they intersect at x=11/2;

or by normal method u hav,
2 cases x-4=x-7,which is an invalid opening.
so the next opening is x-4=-x+7 which gives us , 2x=11 and hence x=11/2
got it ?

Answer 3

yea. but howd u get -x+7?...u just multiplied negative by everything on that side?

Answer 4

wen ever u open a |fn(x)| , u hav 2 cases, opening it as fn(x) or -fn(x) ;

Answer 5

so here we hav x-7 or -(x-7)=-x+7

Answer 6

so why didnt u do the same to lx-4l?

Answer 7

you can try it and it will end with the same exact solution :)

Answer 8

another way to do this is to square both sides
x^2 -8x + 16 = x^2 -14x + 49
the x^2 disappear to leave a simple eqaution

Answer 9

i actually did it, sorry i din't do it explicitly.
since you hav 2 |fn(x)| u hav actually four combinations of openin,
++
+-
-+
--
but case 1,4 and 2,3 are the same , so it looked as if i din't apply it on x-4,
u cud've as well worked like -x+4=x-7 and end up getting the same answer :)

Answer 10

ok. thanks