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Mathematics 20 Online
OpenStudy (anonymous):

for chad dv/dp=-v/p

OpenStudy (anonymous):

dv/v=-dp/p integrating both sides ln|v|=-ln|p|+C

OpenStudy (anonymous):

ln|v|+ln|p|=C

OpenStudy (anonymous):

Uzma

OpenStudy (anonymous):

yes?

OpenStudy (anonymous):

is that all the full solution

OpenStudy (anonymous):

Uzma wer are you

OpenStudy (anonymous):

That could be enough or you can simplify it even more. \(\ln |v|=-\ln |p|+c \implies v=ke^{-p}\), where \(k\) is another constant \(k=e^c\).

OpenStudy (anonymous):

I am a little busy now, I will help you when I get time.

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