Question

Stan invested $17,000, pat at 18% and part at 4%. If the total interest at the end of the year is $1,380, how much did he invest at each rate?

Answer 1

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Answer 2

if he invested P at 18% then he invested the rest, 1700-P and 4%
set
\[.18P+.04(1700-P)=1380\] and solve for P

Answer 3

\[.18P+68-.04P=1380\]
\[.12P=1380-680=1312\]
\[P=\frac{700}{.12}=583\tfrac{1}{3}\]

Answer 4

typo on first line. should be
\[.18P+680-.04P=1380\]

Answer 5

damn and on the second line too! should be
\[.12P=1380-680=700\] answer is right tho...

Answer 6

so the answer is 700 than right