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OpenStudy (anonymous):

Needs help with Surds i Do

OpenStudy (anonymous):

as in \[\sqrt{32}\]?

OpenStudy (anonymous):

Yeah i need hel with them

OpenStudy (anonymous):

for instance, i can't add them, subtract them, simplify them

OpenStudy (anonymous):

name one!

OpenStudy (anonymous):

kk 2 secs

OpenStudy (anonymous):

ok, let's start simple with a simple, \[\sqrt{48}\]

OpenStudy (anonymous):

4 times 8 its irrational not a whole number its between four and eight

OpenStudy (anonymous):

ok find a perfect square inside 48 \[\sqrt{48}=\sqrt{16\times 3}=\sqrt{16}\times \sqrt{3}=4\sqrt{3}\]

OpenStudy (anonymous):

i don't get it

OpenStudy (anonymous):

ah, that's makes sense

OpenStudy (anonymous):

good

OpenStudy (anonymous):

\[\sqrt{50}=\sqrt{25}\times \sqrt{2}=5\sqrt{2}\]

OpenStudy (anonymous):

so\[\sqrt{32}\] = 16sqrt2

OpenStudy (anonymous):

then 4sqrt 2?

OpenStudy (anonymous):

\[\sqrt{x^3}=\sqrt{x^2}\times \sqrt{x}=x\sqrt{x}\]

OpenStudy (anonymous):

not \[16\sqrt{2}\] but rather \[\sqrt{16}\sqrt{2}\] and since you know that \[\sqrt{16}=4\] you get it

OpenStudy (anonymous):

ok, what about square root 50?

OpenStudy (anonymous):

find a perfect square inside of 50 via \[50=25\times 2\]

OpenStudy (anonymous):

sorry, i can see what you mean up there, i need more examples

OpenStudy (anonymous):

first off you believe \[50=25\times 2\] yes?

OpenStudy (anonymous):

and it is always true that \[\sqrt{ab}=\sqrt{a}\times \sqrt{b}\]

OpenStudy (anonymous):

which means \[\sqrt{50}=\sqrt{25\times 2}=\sqrt{25}\times \sqrt{2}\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

the point being that \[\sqrt{25}\] is a number that you know. it is 5.

OpenStudy (anonymous):

so \[\sqrt{50}=5\times \sqrt{2}\]

OpenStudy (anonymous):

so in iother words, you split it, the root the larger numer?

OpenStudy (anonymous):

the root and the "perfect square" yes

OpenStudy (anonymous):

the point is not that it is larger, but rather that it is a perfect square, so you know the square root

OpenStudy (anonymous):

Ok, i get it now

OpenStudy (anonymous):

so for example you know that \[\sqrt{100}=10\] yes?

OpenStudy (anonymous):

so \[\sqrt{200}=10\sqrt{2}\]

OpenStudy (anonymous):

because 200 = 2*100

OpenStudy (anonymous):

ah so what to do when adding together?

OpenStudy (anonymous):

alo is there any way to save conversations?

OpenStudy (anonymous):

and adding together 2 surds

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