Question

Given: f(x)= 3x^2-3x and g(x) = x^2 +x -12
find the domain f/g

Answer 1

set the denominator = 0 and solve. your answer will be all real numbers except...

Answer 2

I got x=4 and x=-3, but 4 is ok so only 3 or -3

Answer 3

ok I did it right ayay!!!

Answer 4

\[x^2+x-12=0\]
\[(x+4)(x-3)=0\]
\[x=-4\] or
\[x=3\]
all real numbers except -4 and 3

Answer 5

think you factored correctly but solved incorrectly yes?

Answer 6

why not -4< i know it factors that way bu tplug it in?

Answer 7

your factors are (x+4)(x-3) so your solutions are -4 and 3 yes?

Answer 8

yes
so would the answer be (-infinity,-4) u (-4,3) U (3, infinity)

Answer 9

\[(x+4)(x-3)=0\]
\[x+4=0\]
\[x=-4\] or
\[x-3=0\]
\[x=3\]

Answer 10

yes you got it!

Answer 11

which is a rather wordy way of saying all numbers except -4 and 3

Answer 12

yipee! the only part I dont get is why -4, I know is factors down to that, but it doesnt make the equations numerator =0?