Given: f(x)= 3x^2-3x and g(x) = x^2 +x -12
find the domain f/g

Question

Given: f(x)= 3x^2-3x and g(x) = x^2 +x -12 
find the domain f/g

anonymous · Answer

set the denominator = 0 and solve.  your answer will be all real numbers except...

anonymous · Answer

I got x=4 and x=-3, but 4 is ok so only 3 or -3

anonymous · Answer

ok I did it right ayay!!!

anonymous · Answer

$$x^2+x-12=0$$
$$(x+4)(x-3)=0$$
$$x=-4$$ or 
$$x=3$$
all real numbers except -4 and 3

anonymous · Answer

think you factored correctly but solved incorrectly yes?

anonymous · Answer

why not -4< i know it factors that way bu tplug it in?

anonymous · Answer

your factors are (x+4)(x-3) so your solutions are -4 and 3 yes?

anonymous · Answer

yes
so would the answer be (-infinity,-4) u (-4,3) U (3, infinity)

anonymous · Answer

$$(x+4)(x-3)=0$$
$$x+4=0$$
$$x=-4$$ or 
$$x-3=0$$
$$x=3$$

anonymous · Answer

yes you got it!

anonymous · Answer

which is a rather wordy way of saying all numbers except -4 and 3

anonymous · Answer

yipee! the only part I dont get is why -4, I know is factors down to that, but it doesnt make the equations numerator =0?