Question

Put the equation in standard form for an ellipse. 9x^2-54x+16y^2+32y=47

Answer 1

its an ellipse!

Answer 2

by the same method i told for hyperbola:
factorise both x and y term.
u get 9(x-3)^2+16(y+1)^2=144
therefore, (x-3)^2/16+(y+1)^2/9=1.

Answer 3

\[9(x^2-6x)+16(y^2+2y)=47\]
\[9(x^2-6x+9)+16(y^2+2y+1)=47+9*9+16*1\]
\[9(x-3)^2+16(y+1)^2=144\]
\[\frac{(x-3)^2}{16}+\frac{(y+1)^2}{9}=1\]

Answer 4

oh it actually does say ellipse in your sentence up there. lol
i thought i was pointing something out

Answer 5

haha ; thanks!!! is it the same way as a hyperbola?

Answer 6

yes the only different is you will have a minus sign between instead of a plus

Answer 7

minus where?

Answer 8

oh i see, hehe