Can you still use the substitution method to solve the following problem since x and y are both squared in the first but not the second??? x^2+y^2=2 y+3x=-2
Any help or advice would be appreciated!!! :)
I only have one more problem after this one brackett I promise!! Thank you so much for all your help, if i could pay you, I would lol..
yes u can use it...but finally check for the answers u got. sometimes u get extreneous roots. i guess u don't hav to worry about them here. ps:lol its just mutual help :D and remember if x1 value gives y1 then they both go together as a solution . don't mix up x1 with y2.
can I tell you what I get using the sub method and u check and help from there?
x^2+3x+y^2=0???
yea i'll be glad , but i'm sorry ... its 6 in the morning here and i'm yet to crash . feeling bloody sleepy...guys will come around and help u :) bye
Thats fine thanks for your time and help Hopefully I can get this one answered
Are you staying to help me on this problem???
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