Calculus-Optimization: The product of two positive numbers is 54. Fnd the numbers if the sum f the first number plus the square of the second number is as small as possible
malevolence u disappeared again lol your just giving me the answer and i dont understand
Okay from x+(54^2/x^2)=s. Taking the derivative. What confuses you?
how u found the derivative of the 2nd part...
Okay. (i'm going to call 54^2=a, its easier to write) Rewrite it as: x+ax^(-2)=s. Because a/x^2=ax^(-2). Follow me up to that point?
yes
:)
Okay, then you have a power rule d/dx(x^n)=nx^(n-1) So: It becomes 1+(-2)a(x^(-3))=0. Right?
ok so we just pretty much ignore the 54...thats what confused me i thought since it was (54/x)^2 we would use the chain rule...no?
The 54 is just a constant, you can pull it out of a derivative. So its immaterial. (I just called it a for convenience).
You can use the chain rule. You would have (2)(54x^-2)(-1)(54/x)
Convince yourself that those are both equally valid. :P
ok...i'm sorry for my slow moment im very good with derivatives but...with optimization i dont know if i should multiply or which rule's i should use thanks so much lol
u think if i use the chain rule i would get the same answer?
Thats what I did above^^ Yes you will. If you multiply what I have together up there, you get the same thing.
oh ok THANKS SO MUCH..i dont know why im so confused with optimization
No problem, after you do it a bunch it'll become easy. :P Just post any questions you have and I'll try to explain a little better.
ok! thanks
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