Find the remainder when P(x)= x^4 -3x^3 +4x^2 +5 is divided by x+2
when I did it I got 61, but if others would like to confirm this..long time since I done long division.
\[(x+2)(x ^{3} -5x ^{2}+14x-28)\]
Thank you! You're probably right. Would this work with synthetic as well?
Dont understand the question..explain?
Would you be able to divide using synthetic division?
I dont know what synthetic division means...is it like long division...I've been doin maths for some time now, and I've never heard of this term.
Nevermind then. It's Algebra II. D:
I have no problem with algebra, give me a question and I will tell you how to do it.
and u are a noob^
and u are a noob^
is that question for me joeymason or for ginamercedes
Do you know how to do this one? Find the equation of the perpendicular bisector of the line connecting P(-4, 6) and Q(4, -2).
yes
the equation of a line: \[y _{2}-y _{1}=m(x _{2}-x _{1})\]
y2=-2, y1=6, x2=4, x1=-4
now for m(the slope) \[m=y _{2}-y _{1}/x _{2}-x _{1}\]
-2-6 / 4+4 So -8/8 -1?
if you fill in the values in these equations you will have the line that connects your two points. the perpendicular bisector will be a line which is perpendicular. you already know the slope of your line..lets say b/a, then the slope of the perpendicular line is -a/b
So from here, I just plug it in?
now, the perpendicular line is the opposite slope
so if your slope is a/b, then the slope of the perpendicular line is -b/a
sorry for the delay my system crashed had to reboot
It's okay, thank you for your assistance thus far.
now you have the slope of the perpendicular bisector, you need to find a point on that line
to do this we find the midway point (hence the term bisector) which means cut in half
the midway point is simply \[x _{1}+x _{2}/2, y _{1}+y _{2}/2\]
once you have that you have the slope and one point on the line, you can then get the equation of the line
in this case as you said the slope is -1
or -1/1 therefore the slope of the perpendicular is -(1/-1) = 1
now the bisector (point) is -4+4/2=0/2=0 and 6+(-2)=4 so your midpoint (the point on your line is (0,4)
then putting this into the equation y-y1=m(x-x1) we get the following
y-4=1(x-0) or y-4=x which becomes: y=x+4
I hope that answers your question!
Thank you so much!!!
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