Question

The sum of a two digit numer is ten. If the digits are reversed, the new umber is fifty-four moe than the original number. Find the original number.

Answer 1

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Answer 2

let digits of original number be xy

in that order

Answer 3

so x+y=10 ( one eqn )

Answer 4

reversing the digits ( yx ) gives 54 more than the original

Answer 5

ie

(y * 10 ) + x = 54 + ( x*10) +y

Answer 6

two eqns , two unknowns

Answer 7

you can solve

Answer 8

remember the number "xy" = (x*10) + y

because we have x in the 10'splace and y in the ones place

Answer 9

thats a slightly different question I havent seen before

Answer 10

so x+y=10

and 9x -9y +54 =0

solve those simultaneously to find x and y , you can do that

Answer 11

then the original number will be x followed by y

so if you find x=4 and y=6

the orginal; number would have been 46

Answer 12

substitutoin right

Answer 13

could do anything you want, doesnt really matter

Answer 14

you could divide the 2 eqn by 9 , and then add the eqns

and solve by elimination