How do you find the indefinite integral of [(1+e^x)^2]/e^x?
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So you have: \[\int\limits \frac{(1+e^x)^2}{e^x}dx\]
\[\int\limits \frac{(1+e^x)^2}{e^x}dx\]\[\int\limits\frac{1+2e^x+e^{2x}}{e^x}dx=\int\limits e^{-x}dx+\int\limits 2dx +\int\limits e^xdx\]
Multiply the top out. Then divide the e^x through leaving: \[\int\limits \frac{1+2e^x+e^{2x}}{e^x}dx=\int\limits [e^{-x}+2+e^x]dx\].
-e^x+2x+e^x=2x+2sinhx
Then from there its straight forward: I=-e^-x+2x+e^x+c=2x+2sinh(x)+c
Haha, at least I wasn't the only one noticing the hyperbolic trig :D
Make sense blue?
I get that, thanks :D
:D
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