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which is the equation of a line that has an x-intercept of -3 and is perpendicular to the line 2x-y=1? How do you solve it?
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the given line slope is 2 , our line slope is perp on it then our line slope is -2
our line has x intercept at -3 then point (-3,0) lyes on it
what would the equation be?
equation should be y / (x+3) = -2
y = -2x-6
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wait so how exactly did you get that?
i already said how i got it :)
fine
bnb is incorrect. if the slope of a given line is m, then the perpendicular to that line will have a slope -1/m
so the equation will be y/(x+3)=-1/2 and dat'll giv us 2y+x+3=0.
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x+2y+6=0
ops my bad , thanx brackett
:)
ops my bad , thanx chutzpah!
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