Question

In 4x^2-25y^2z^2, would the answer be (2x+5yz)(2x-5yz)?

Answer 1

I am not sure on this one. It was harder to solve. Could you please double check my work?

Answer 2

what is the ln? is it
\[\ln(4x^2-25x^z^2)\]

Answer 3

i mean
\[\ln(4x^2-25y^2z^2)\]

Answer 4

or is that 'ln' just a typo?

Answer 5

if it is
\[\ln(4x^2-25y^2z^2)\] then you factored properly to get
\[\ln((2x+5yz)(2x+5yz))=\ln(2x+5yz)+\ln(2x-5yz)\]

Answer 6

there is no ln in the problem. :(

Answer 7

no that is In not LN.

Answer 8

I think he was saying 'in' not 'ln', right?!

Answer 9

then you were right at the beginning and i should just be quiet