Question

What makes this a perfect square trinomial? x^2+22x+?
Is the ? 11

Answer 1

because 11*2 is 22

Answer 2

11^2

Answer 3

Wait the answer is 11^2? But wouldn't that be 121?

Answer 4

\[(a+b)^2=a^2+2ab+b^2\]
and here a = x, 2ab = 22x making b 11, and therefor you want
\[x^2+22x+121=(x+11)^2\]\]

Answer 5

\[?=121\] yes

Answer 6

11. yes

Answer 7

????

Answer 8

this is not an equation. the question was what should the constant be to make the expression a perfect square. the answer is the constant should be 121 so you will have a perfect square, namely
\[(x+11)^2=x^2+22x+121\]