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what is the value of c? 4x^2-32x+c. 8?
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because 8*4 is 32
so that you have a perfect square?
yes. I think so. a perfect square trinomial.
\[4=2^2\] yes? and we want \[-32=-2\times 2\times c\]
so yes 8 is right!
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(2x-8)^2.... c=64?
Really? I got it right?
would it be 8^2 for 64 or just 8?
pmel is right it is 64
and I thought \[c \approx 200000 m/s^2\]
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b is 8 so b^2=64
haha
pmel has it. you want a perfect square and it will look like \[(2x-b)^2\] \[b=8\] \[b^2=64\]
in general, when working with perfect square quadratics the last term c is larger than the middle term b is ax^2+bx+c because for all numbers greater than 2 the value (arbitrary constant d) d^2>d+d.
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