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Would the ? in 16x^2+?x+36 be 6?
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Oops I mean 4.
36 is the square of ___
6.
16 is the square of ___
4
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4
\[2\times 6\times 4 =?\]
48
you win
48
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48? But why is it 48?
ok
because \[(a+b)^2=a^2+2ab+b^2\]
here \[a=2x\] \[a^2=4x^2\] \[b=6\] \[b^2=36\] and you are looking for \[2ab\]
if this is a perfect square, than the vales A and C perfectly constrain the values of a and c in Ax^2+Bx+C=(ax+c)^2.
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OH. Thank you. That helps a lot.!
yw
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