Question

Limit (t^3 + t^2 - 5t +3 / t^3 - 3t + 2)
t tends to -1

Answer 1

lim t->-1 of (t^3+t^2-5t+3)/(t^3-3t+2) u first substitue the value t=-1 in the limit ...
in the numerator we hav
(-1)^3+(-1)^2-5(-1)+3=8
in the denominator we hav
(-1)^3-3(-1)+2=4
u find that it does not take any indeterminate form... and hence the limit is 2.