find the value of b such that the system of equations bx-15y=-20 4x+10y=-17 does not have a solution. what is b=???
what is the condition for two lines not to have a solution?
b = - 6 ?
not sure what your question is. but what is b? that's all i need to know. and how to find it. I've done this long time ago can't remember how to do these.
nice going dhatra :)i like ur approach :)
well, two lines are said to have a solution at the point of their intersection. if the two lines are parallel, then they will not intersect, and hence will not have a solution. two lines are parallel if 1. they have the same slope 2. they are separated by some distance.
why thank you, brackett. :)
dhatraditya. Explain to me, how would you solve for the variable b?
first lets rearrange each equation to the form y = mx+b
@beehive: for the equations to hav no solution, the lines must be parallel and hence their slope has to be same...therefore u hav b/15=-4/10 and so u get, b=-6
yup, as brackett said.
brackett how did you get here? b/15=-4/10 ????
i equated both the slopes
@ beehive: rearrange both the equations in the slope intercept form, ie y = mx+b and post what you get.
do you know how to rearrange the equations, beehive?
yes i do. hold on a sec. I'm trying to get this straight in my head. i've done this like 4 years ago. forgot it all.
alright, whenever you are ready
for the first one. i got \[y=\frac{-bx}{-15}+\frac{4}{3}\] the second one i got. \[y=-\frac{2}{5}x-\frac{17}{10}\] this seem right?
right. that is correct. now, for two equations expressed in the slope intercept form to be parallel, their slopes must be equal. so -b/-15 = -2/5
well i understand you can rewrite the y=(-bx)/(15) to \[y=\frac{-b}{15}x\]
ok i see. Thanks.
no, -bx/-15 = -1*bx/-1*15 = bx/15
you are welcome
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