Question

evaluate lim t approaches -3 (t^2-9)/(2t^2+7x+3)

Answer 1

You need to use l'Hopitals rule for this one.

Answer 2

12/5

Answer 3

yes i know i factor out the numerator now i need help on the deonomotinor

Answer 4

Oh. I suppose factoring works well here..
\[2t^2 + 7t + 3 = (2t + 1)(t + 3)\]
So t+3 will cancel with the t+3 on the top.

Answer 5

And you get (-3-3)/(2(-3)+1) = -6/-5 = 6/5

Answer 6

thanks again