Question

5th square root how do you solve them?

Answer 1

You mean the 5th root? You generally plug it into your calculator ;p

Answer 2

You can do it by approximating, but it's long and tedious.

Answer 3

the following equation
\[\sqrt[5]{64t^{17}u^{15}}\]

Answer 4

sorry. what i mean is how to simplify them.

Answer 5

Oh. Just recall that:
\[\sqrt[a]{b^k} = b^{k\over a}\]
And simplify the fractions in your exponents.

Answer 6

So for example:
\[64 = 2^6 \implies \sqrt[5]{64} = \sqrt[5]{2^6} = \sqrt[5]{2^5\cdot 2} = 2\sqrt[5]{2}\]

Answer 7

polpak i get that. i don't get how to do the exponents.

Answer 8

I just explained..
\[t^{17} = t^{15}\cdot t^2 \implies \sqrt[5]{t^{17} } = \sqrt[5]{t^{15} \cdot t^2} = t^{15/5}\sqrt[5]{t^2} = t^3\sqrt[5]{t^2}\]

Answer 9

Does that make sense?

Answer 10

yeah that makes sense.

Answer 11

ok. so this is what i got for the answer.
\[2t^3u \sqrt[5]{2t^2}\]
when simplified the radical form.

Answer 12

Yep.

Answer 13

Wait, no

Answer 14

appreciate it polpak.

Answer 15

Should be \(u^3\)

Answer 16

sorry my bad. I wrote the problem wrong.
since it should be
\[\sqrt[5]{64t^{17}u^5}\]
ends up to be correct. small mistake on my end.

Answer 17

Oh I see. Yes.