Give the value of x where f(x)= (x^2-4)/(x^2+x-2) has a JUMP discontinuity? (Not sure how to figure this one out)
u cant have junp unless its given in the ques
how come?
Yay SAt is here! thanks to you guys I managed to crack 100 on my test!
hello congrats
you want to teach at the university? :-)
factor and cancel get \[\frac{x-2}{x-1}\]
i think its x = 1, i guess you consider a vertical asymptote where the function goes in opp directions a jump discontinuity
I did that for removable
which would exist at the point where a hole is at - correct?
but, how does factoring help with jump?
or even infinite disc.?
well for every other x the function is defined and continuous
is that because it/they factor out?
wouldnt the vertical asymptote be where you;d find infinite discontinuity?
possibly, not sure about this one but either way its x=1
i don't consider it a jump discontinuity because there is no jump. but maybe i am wrong
jump discont usually comes from a piecewise function
greatest integer function for example
i agree, but maybe if you consider limits it jumps from pos infinity to neg infinity
hmm we are only thinking that because that is what the question asks yes? i mean otherwise we would day "infinite' discontinuity or "vertical asymptote" or "pole" not jump.
i wonder where this question came from
yes ive never heard it used this way before, but maybe it is
maybe it is by whomever wrote the question!
ahh got it, answer is No solution then
haha, that's what I said.
for jump it is DNE, while for removable it shld be -2 ( I think), while for infinite I'm stumped
then the infinite is x=1
this might help
aha! so 'there is none" is the correct answer. whew! didn't know that was a choice
and now i can rest easy. good night
sorry
sat which one are you ssaying is none?
haha, i dont think the removable exists either f(-2) = 4/3
prof explained removable to be a hole
yes, there is no hole at -2
but, if you factor it out you shld have a hole at x=-2?
how so? the (x+2) cancels out leaving a continuous function except for the asymptote
isn;t that the exact explanation of a hole: where the factors will cross out?
btw, thanks for taking the time to help!
np hmm maybe i have forgotten some stuff try graphing the function (x-2)/(x-1) and you will notice there is no hole
I agree with you, Im going from what the teach is saying :-) in class....
well better go with the teacher :)
haha - thanks man. will do for the remov, but for the jump and infinite?
jump DNE infinite, x=1
thanks a ton man! triple medals
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