Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

Give the value of x where f(x)= (x^2-4)/(x^2+x-2) has a JUMP discontinuity? (Not sure how to figure this one out)

OpenStudy (anonymous):

u cant have junp unless its given in the ques

OpenStudy (anonymous):

how come?

OpenStudy (anonymous):

Yay SAt is here! thanks to you guys I managed to crack 100 on my test!

OpenStudy (anonymous):

hello congrats

OpenStudy (anonymous):

you want to teach at the university? :-)

OpenStudy (anonymous):

factor and cancel get \[\frac{x-2}{x-1}\]

OpenStudy (dumbcow):

i think its x = 1, i guess you consider a vertical asymptote where the function goes in opp directions a jump discontinuity

OpenStudy (anonymous):

I did that for removable

OpenStudy (anonymous):

which would exist at the point where a hole is at - correct?

OpenStudy (anonymous):

but, how does factoring help with jump?

OpenStudy (anonymous):

or even infinite disc.?

OpenStudy (dumbcow):

well for every other x the function is defined and continuous

OpenStudy (anonymous):

is that because it/they factor out?

OpenStudy (anonymous):

wouldnt the vertical asymptote be where you;d find infinite discontinuity?

OpenStudy (dumbcow):

possibly, not sure about this one but either way its x=1

OpenStudy (anonymous):

i don't consider it a jump discontinuity because there is no jump. but maybe i am wrong

OpenStudy (anonymous):

jump discont usually comes from a piecewise function

OpenStudy (anonymous):

greatest integer function for example

OpenStudy (dumbcow):

i agree, but maybe if you consider limits it jumps from pos infinity to neg infinity

OpenStudy (anonymous):

hmm we are only thinking that because that is what the question asks yes? i mean otherwise we would day "infinite' discontinuity or "vertical asymptote" or "pole" not jump.

OpenStudy (anonymous):

i wonder where this question came from

OpenStudy (dumbcow):

yes ive never heard it used this way before, but maybe it is

OpenStudy (anonymous):

maybe it is by whomever wrote the question!

OpenStudy (dumbcow):

ahh got it, answer is No solution then

OpenStudy (anonymous):

haha, that's what I said.

OpenStudy (anonymous):

for jump it is DNE, while for removable it shld be -2 ( I think), while for infinite I'm stumped

OpenStudy (dumbcow):

then the infinite is x=1

OpenStudy (anonymous):

OpenStudy (anonymous):

this might help

OpenStudy (anonymous):

aha! so 'there is none" is the correct answer. whew! didn't know that was a choice

OpenStudy (anonymous):

and now i can rest easy. good night

OpenStudy (anonymous):

sorry

OpenStudy (anonymous):

sat which one are you ssaying is none?

OpenStudy (dumbcow):

haha, i dont think the removable exists either f(-2) = 4/3

OpenStudy (anonymous):

prof explained removable to be a hole

OpenStudy (dumbcow):

yes, there is no hole at -2

OpenStudy (anonymous):

but, if you factor it out you shld have a hole at x=-2?

OpenStudy (dumbcow):

how so? the (x+2) cancels out leaving a continuous function except for the asymptote

OpenStudy (anonymous):

isn;t that the exact explanation of a hole: where the factors will cross out?

OpenStudy (anonymous):

btw, thanks for taking the time to help!

OpenStudy (dumbcow):

np hmm maybe i have forgotten some stuff try graphing the function (x-2)/(x-1) and you will notice there is no hole

OpenStudy (anonymous):

I agree with you, Im going from what the teach is saying :-) in class....

OpenStudy (dumbcow):

well better go with the teacher :)

OpenStudy (anonymous):

haha - thanks man. will do for the remov, but for the jump and infinite?

OpenStudy (dumbcow):

jump DNE infinite, x=1

OpenStudy (anonymous):

thanks a ton man! triple medals

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!