Question

This is Geometry: Given that two sides of a triangle are 20 and 66. Find the range of possible measures for the third side, s.

Answer 1

i don't have enough yarn for this.

Answer 2

s>9000

Answer 3

okay someone gave me a medal for being funny, so i'll give this question my best shot

Answer 4

that was me

Answer 5

first answer sooo wrong sorry i have multiple choice

Answer 6

i was joking sorry

Answer 7

what are the choices i can tell you which one it is

Answer 8

46<s<86

Answer 9

20^2+66^2=c^2 or 20^2+b^2=66^2

Answer 10

i think, geometry was awhile ago

Answer 11

i just have no clue how to solve this algebraically outside of my head

Answer 12

yay thanks akbr0

Answer 13

OH DUHHH
A2+B2=C2

Answer 14

TIME FOR A REAL SHOWER. I THINK I'LL HAVE MY WHISKEY NOW

Answer 15

(btw, my 2's up there are squares)

Answer 16

if 66 is the longest side then the sum of the other two sides must be > 66.
s+20>66
s>46
if s is the longest side then the sum of the other two sides are greater than s:
s<20+66
s<86
46<s<86

Answer 17

thank you too rsvital

Answer 18

youre welcome